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I have a table as follows: Filename - varchar Creation Date - Date format dd mm yyyy hh24:mi:ss Oldest cdr date - Date format dd mm yyyy hh24:mi:ss How can I calcuate the difference in hours minut
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Viewed 104k times 15 I am trying to make a graph (like a bar graph, number of occurrences on the y and value on the x) that will show each value in a column and the number of times it occurs
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I have a web service that receives data in JSON format, processes the data, and then returns the result to the requester I want to measure the request, response, and total time using cURL My ex
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If that value drops to 0, instead of forwarding the packet, the router simply drops it as the packet is not supposed to live any longer This mechanism is used to prevent a network from flooding by data, as each packet can be passed around only a limited number of times, i e it 'lives' inside of it only for a limited amount of 'time'
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Try the Bash built-in help: help for Output for: for NAME [in WORDS ;] do COMMANDS; done The `for' loop executes a sequence of commands for each member in a list of items
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If you are not expert in SQL, you should not be considering using a loop There are only a few conditions where one is needed and most of the rest of the time, using a loop is the equivalent of pushing your car instead of driving it
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N-Suffix the table aliases that you will use multiple times to make it obvious *One way DBAs avoid the headaches of updating natural keys is to not specify primary keys and foreign key constraints which further compounds the issues with poor db design I've actually seen this more often than not
- How to count occurrences of a column value efficiently in SQL?
and if data in "age" column has similar records (i e many people are 25 years old, many others are 32 and so on), it causes confusion in aligning right count to each student in order to avoid it, I joined the tables on student ID as well
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