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    A C++ question, I know int* foo (void) foo will return a pointer to int type how about int foo (void) what does it return? Thank a lot!
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    The internal representation of int and unsigned int is the same Therefore, when you pass the same format string to printf it will be printed as the same However, there are differences when you compare them Consider: This can be also a caveat, because when comparing signed and unsigned integer one of them will be implicitly casted to match
  • int* i; or int *i; or int * i; - i; - Software Engineering Stack Exchange
    64 I prefer int* i because i has the type "pointer to an int", and I feel this makes it uniform with the type system Of course, the well-known behavior comes in, when trying to define multiple pointers on one line (namely, the asterisk need to be put before each variable name to declare a pointer), but I simply don't declare pointers this way
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    The question "what is the difference between int* and int []?" is a less trivial question than most people will think of: it depends on where it is used In a declaration, like extern int a[]; it means that somewhere there is an array called a, for which the size is unknown here In a definition with aggregate initialization, like int a[] = { 1, 2, 3 }; it means an array of a size I, as
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    In C#, int and Int32 appear to be the same thing, but I've read a number of times that int is preferred over Int32 with no reason given Are the two really the same? Is there a reason where one sho
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    int (*f)(int, int) = dlsym( shared_lib, "foo" ); They're also handy for building table-driven code - I once wrote a utility to load and parse different types of data files from various scientific instruments and load them into a database, each of which had slightly different formats based on the instrument and type of data
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