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- Whats the difference between 2O and O2 [duplicate]
$\ce {2O}$ is basically two atoms of oxygen, unbonded and separate On the other hand, $\ce {O2}$ is oxygen molecule, which is more commonly called oxygen gas
- diH2O, dH2O, and DI H2O. What do they mean?
What do $\ce {diH_2O, dH_2O}$, and $\ce {DI H_2O}$ mean? I'm not asking for a description of deionized water and distilled water I'm asking what the three abbreviations formulas mean In other wor
- Reaction of glucose acetal with acetic anhydride
Starting from any cyclic form of glucose, there are two key ways to form the acetal in sequence (i) Taking glucopyranose as a starting point, here is a reaction scheme: Initially, you could argue that you can protonate either the free hydroxy group (left-hand path) or the cyclic oxygen (right-hand path) The two paths give you either of the two aldehydes in the third row The left-hand path
- What is the IUPAC name of N2O? - Chemistry Stack Exchange
What is the IUPAC name of $\ce {N2O}$? I would usually say it's "dinitrogen monoxide", but its name is written as "dinitrogen oxide" in my textbook I don't understand how that
- How do you find the enthalpy of solution of a hydrated salt?
I take a hydrated salt ($\ce {Na_2CO_3 \cdot 10H_2O }$), heat it for a certain amount of time (say 2 minutes) and then measure the enthalpy of solution of the salt
- CH4 + O2 = gt; CO2 + 2H2, whats wrong with it?
There's nothing wrong It's incomplete combustion It is one of a number of oxidizing reactions that can and will be occurring if you are burning this hydrocarbon in an oxygen-restricted environment But the dominant reaction will be the one where the lowest energy state is reached So you will likely wind up with one CO molecule, one water molecule and one hydrogen molecule instead
- Na2HPO4 is amphoteric: write the two reactions
$\\ce{Na_2HPO_4}$ is amphoteric, which means it can act as a base or as a acid depending on which substance they react with This is the reaction in which disodium phosphate appears to be an acid:
- home experiment - Reaction between sodium carbonate and water . . .
The answer lies in the cost of the processes : investments, availability of reactants, price of energy, etc Calcinating sodium carbonate at more than 100°C actually gives off sodium oxide ($\mathrm {Na_2O}$), but it also releases $\mathrm {CO_2}$ in the atmosphere, and you have to obtain sodium carbonate first This is no commonplace mineral
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